16x^2=47x+30

Solution for 16x^2=47x+30 equation:

16x^2=47x+30

We move all terms to the left:

16x^2-(47x+30)=0

We get rid of parentheses

16x^2-47x-30=0

a = 16; b = -47; c = -30;
Δ = b2-4ac
Δ = -472-4·16·(-30)
Δ = 4129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-\sqrt{4129}}{2*16}=\frac{47-\sqrt{4129}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+\sqrt{4129}}{2*16}=\frac{47+\sqrt{4129}}{32}
$